Sunday, 12 August 2012

A quick hand combination

Here's a quick first problem:

How do you play 10 9 7 6 opposite A 4 3 2 for only two losers? You may assume plenty of entries to either hand.
Posted by David on
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2 comments:

  1. adskal18 August 2012 at 05:04

    The hunch is 10 from the hand (run), I guess the hunch is correct (covers singleton 8 on the right and single honour on the left).

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    Replies
    1. David19 August 2012 at 10:06

      Yep, not some horrible problem that take a page to explain the answer to. :)
      This line beats just playing the ace only by picking up the singleton 8 offside.

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